the length of a rectangle is 7 centimeters less than the width. What are the dimensions of the rectangle if its area is 228 square centimeters?

W = 38 L = 31

Step-by-step explanation:

L = W - 7

L X W = 228 cm^2

(W - 7 ) W = 228                 substitute

W^2 - 7 W = 228                distribute

W^2 - 7W - 228 = 0            move to the same side and factor

(W +24) (W-38) =0             Or Use the quadratic formula

We can't have a negative area, so ignore the - 24, plug into original equation

W= 38    and    L = 31

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

question:

could we have options?