.
is the same as saying 
.
using the definition of 
as an x-value.![f(x)=x^{3}-4x+2\\g(x)=x^{2}+2\\\\(f*g)(x)=f(g(x))\\\\(f*g)(x)=(x^{2}+2)^{3}-4(x^{2}+2)+2\\(f*g)(x)=[ (x^{2}+2)(x^{2}+2)(x^{2}+2) ] -4x^{2}-8+2\\(f*g)(x)=[ (x^{4}+4x^{2}+4)(x^{2}+2)]-4x^{2}-6\\(f*g)(x)=x^{6}+6x^{4}+12x^{2}+8-4x^{2}-6\\(f*g)(x)=x^{6}+6x^{4}+12x^{2}-4x^{2}+8-6\\(f*g)(x)=x^{6}+6x^{4}+8x^{2}+2](/tpl/images/1208/8232/9b5a8.png)
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