6x-5y-z=7 i have to eliminate x
the full question is
2x+y-3z=5
2x+3y+z=13
6x-5y-z=7

2y - 20z = -16

Step-by-step explanation:

6(2x+y-3z) = 5(6)

=> 12x + 6y- 18z = 30

3(2x + 3y + z) = 13(3)

=> 6x + 9y + 3z = 39

Now minus the top equation from the bottom two:

12x + 6y - 18z = 30

6x + 9y + 3z = 39

6x - 5y - z = 7

12x + 6y - 18z = 30

12x + 4y + 2z = 46

Minus top from bottom:

2y - 20z = -16

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: