What is the initial value in the equation f(x) = 350(1 - 0.12)^x? *

Given:

The function is:

To find:

The initial value of the function.

Solution:

We have,

The value of the function at x=0 is called the initial value of the function.

For x=0, we get

Clearly 0.88 is a non zero number and zero to the power of a non zero number is always 1.

Therefore, the initial value of the function is 350.

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step-by-step explanation: