Read the problem. Jordan and Roman travel the same route to work. Jordan leaves for work one morning and drives at a rate, r, of 56 mph. Roman leaves the house soon after, when Jordan has already traveled 2 mi. Roman drives at a rate of 60 mph. How long after Jordan leaves home will Roman catch up to her? How many miles into their commute will this occur?

Which system of equations models this problem?

d = 56t
d = 58t

d = 56t
d = 62t

d = 56t
d = 60t – 2

d = 56t
d = 60t + 2

Step-by-step explanation:

D= 56t

D= 60t -2

D= Distance T=time d = 56t (Jordan) d = 60t - 2 (Roman)

d = 56t d = 60t - 2

56t = 60t - 2 d = 56(1/2) d = 60(1/2) - 2

-60t -60t d = 28 d = 30 - 2 = 28

-4t = -2

t = 1 / 2

step-by-step explanation:

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: