How do I start this problem? I don't need help with the graphing part.

Here's link to the

cutt.ly/LxpA7ye

x = 6 , y = 0   (x , y) = (6 , 0)

x = 12, y = 3   (x , y) = (12 , 3)

x = 24, y = 9   (x , y) = (24 , 9)

Step-by-step explanation:

Simply plug in a x, and find a y that would make the equation true:

When x = 6:

6 - 2y = 6

6 (-6) - 2y = 6 (-6)

-2y = 0

(-2y)/-2 = (0)/-2

y = 0

When x = 6, y = 0    (x , y) = (6 , 0)

When x = 12:

12 - 2y = 6

12 (-12) -2y = 6 (-12)

-2y = -6

(-2y)/-2 = (-6)/-2

y = 3

When x = 12, y = 3   (x , y) = (12 , 3)

When x = 24:

24 - 2y = 6

24 (-24) - 2y = 6 (-24)

-2y = -18

(-2y)/-2 = (-18)/-2

y = 9

When x = 24, y = 9   (x , y) = (24 , 9)

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the correct answer is the second option

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b