Please help me anyone i need this in 10 minutes

Given:

The rate of interest on three accounts are 7%, 8%, 9%.

She has twice as much money invested at 8% as she does in 7%.

She has three times as much at 9% as she has at 7%.

Total interest for the year is $150.

To find:

Amount invested on each rate.

Solution:

Let x be the amount invested at 7%. Then,

The amount invested at 8% = 2x

The amount invested at 9% = 3x

Total interest for the year is $150.

Multiply both sides by 100.

Divide both sides by 50.

The amount invested at 7% is .

The amount invested at 8% is

The amount invested at 9% is

Therefore, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.

my answer is$ 12

step-by-step explanation:

because 15 -2=12

maybe i can