A line that passes through (-1, 6) and the origin

The equation is y = -6*x

Step-by-step explanation:

I suppose that we want to find the equation for a line that passes through the point (-1, 6) and the origin (remember that the origin is the point (0,0))

A general linear equation is written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

If this line passes through the points (x₁, y₁) and (x₂, y₂), then the slope of the line is equal to:

a = (y₂ - y₁)/(x₂ - x₁)

Now we know that our line passes through the points (0, 0) and (-1, 6), then the slope is:

a = (6 - 0)/(-1 - 0) = 6/-1 = -6

Then our equation is something like:

y = -6*x + b

To find the value of b we can use the fact that this line passes through the point (0, 0).

This means that when x = 0, y is also equal to zero.

If we replace these values in the equation we get:

0 = -6*0 + b

0 = b

Then our equation is:

y = -6*x

a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

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