Pls help asap Consider the following pair of equations:

y = 3x + 3

y = x − 1

Explain how you will solve the pair of equations by substitution. Show all the steps and write the solution in (x, y) form.

Step-by-step explanation:

From the second equation, we can plug in x-1 for y into the first equation. It goes as follows: x-1=3x+3

Now we solve for x by adding 1 to both sides, and then subtracting 3x from both sides to get -2x=4

Thus, x=-2.

Now plug that in for y=x-1 and you get -2-1=-3

So, y=-3

To check, let's plug in the pair. -3=3(-2)+3    -3=-3

-3=-2-1

So, the ordered pair is (-2,-3)

(-2, -3)

Step-by-step explanation:

We are given y = 3x + 3 and y = x - 1.

We can substitute y = x + 1 into the y value for y = 3x + 3, so

x - 1 = 3x + 3  Now, we just subtract x from both sides.

-1 = 2x + 3  We subtract 3 from both sides.

-4 = 2x

2x = -4  We divide both sides by 2

x = -2  Now we have our x value - (-2, y)

Let's substitute the x value into both of the equations given.

1st equation:

y = 3(-2) + 3

y = -6 + 3

y = -3

2nd equation:

y = (-2) - 1

y = -3

We now know that both equations give us the same y value when x = -2 is substituted, therefore our solution is:

(-2, -3)

irrational, cannot