1 + x2)( 3 + 3x3) b. ( 3x)(7 -5x3) c. (3 – 2x3)(4 – 2x + 2x – 3x2 + 4x3) d. (12x2 – 5x4 -11x6 + 4x – 24)(- 6x3) e. (x2 – x5 – x)(-3x5) f. (5x4 – 3x2 -1)(5x5 – 3x3) g. (13 + 2x3 + 3x2+ 6x)(-3 -4x) h. (2x5 + 3x4 – 4x3 + 5x2 – 6x)(4x + 5) i. (6b2 + 3b4 – 12)(-4b +6) j. (13 – 14d)(3b2 + 4b – 5b3) k. (21d6 +3d5 +6d4 – 3d3- 4d2 +12)(7d) l. (21d6 +3d5 +6d4 – 3d3- 4d2 +12)(7d + 9) m. (3 – 2x3 +3x2 )(4 – 2x + 2x – 3x2 + 4x3) n. (4m5-3m2+5m4-8m3+4m)(-m4)

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

answer: 1.06 km per sec

step-by-step explanation:

39.6 m=63.72 km

60 min in an hour so 63.72/60=1.06

if i'm not wrong, i would say that the third angle has (72) because the three sides of all triangles have 180 degrees and if we subtract 180 - 62 - 40 = (72) / but i'm not sure about 40 yd.