An unopened cereal box contains `15/28` cubic foot of cereal. If the box is full, and the length and height of the box are `5/7` and `1(1)/(2)` feet, respectively, what is the width of the box? A. `1/2` foot B. `1/7` foot C. `3/5` foot D. `4/7` foot

A. `1/2` foot

Step-by-step explanation:

The computation of the width of the box is shown below:

15 ÷ 28 = (5 ÷ 7)(1 1 ÷ 2)(width)

15 ÷ 28 = (5 ÷ 7)(3 ÷ 2)width

15 ÷ 28 = (15 ÷ 14)width

(15 ÷ 28) ÷ (15 ÷ 14) = width

(15 ÷ 28) × (14 ÷ 15) = width

w = 14 ÷ 28

= 1 ÷ 2 ft

a

Step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

answer: 0.64

step-by-step explanation: