When solving the system of equations 3x−3y=1 and −2x+4y=2 algebraically, a good first step is to: A. Multiply 3x−3y=1 by 2, and multiply −2x+4y=2 by 3.
B. Multiply 3x−3y=1 by 3, and multiply −2x+4y=2 by −2.
C. Rewrite both equations in slope-intercept form.
D. Add the equations together.

A. Multiply 3x−3y=1 by 2, and multiply −2x+4y=2 by 3.

Step-by-step explanation:

Given

Required

A good first step

A good first step is to eliminate x and this is done as follows:

Multiply by 2 (gotten from coefficient of x in the second equation)

Multiply by 3 (gotten from coefficient of x in the first equation)

This gives:

Add both equations

Hence (a), is true

828. all there is to it!

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2/3

step-by-step explanation:

the slope of a line is equal to the rise/run. in this case the line rises 2 units for every +3 units it moves