14. Given that log 2 = 0.3010 and log 3 = 0.4771 , how can we find log 6 ? A. log6 = log2 x log3 = 0.3010 x 0.4771
B. log6 = log2 + log3 = 0.3010 + 0.4771
C. log6 = log2 – log3 = 0.3010 – 0.4771
D. log6 = log2 = log3 = 0.3010 = 0.4771

B. log6 = log2 + log3 = 0.3010 + 0.4771

Step-by-step explanation:

log 2 = 0.3010

log 3 = 0.4771

log 6 = ?

6 = 3 * 2

log 6 = log (3 * 2)

According to log rules;

log (a * b) = log(a) + log (b)

This means;

log 6 = log 3 + log 2

Inserting the values they represent;

log 6 =  log 3 + log 2 =  0.4771  + 0.3010

Correct option:

B. log6 = log2 + log3 = 0.3010 + 0.4771

answer: the answer is 30 miles per hour.

ft/s -> mphmph = ft/s 1.466667mph = 44 divided by 1.466667mph = 30.00000

- r3ktforgood ☕