What the answer?
i need help​

2m-3/m^2-9

Step-by-step explanation:

1/m+3 + m/m^2-9

= 1/m+3 + m/(m+3)(m-3)

= 1(m-3)/(m+3)(m-3) + m/(m+3)(m-3)

= (m-3)+m/(m+3)(m-3)

=2m-3/m^2-9

the radius is 2 times the diameter.

step-by-step explanation:

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.