What is the inverse of H(x)=1/2x+3

(x) = 2x - 6

Step-by-step explanation:

let y = h(x) and rearrange making x the subject

y = x + 3 ( multiply through by 2 to clear the fraction )

2y = x + 6 ( subtract 6 from both sides )

2y - 6 = x

Change y back into terms of x with x = (x)

(x) = 2x - 6

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step-by-step explanation:

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