The length of a rectangle is 4 yd more than twice the width x. The area is 390 yd. Find the dimensions of the given shape.

Step-by-step explanation:

step 1. let l be the length of the rectangle

step 2. l = 2x + 4

step 3. lx = 390 yd^2

step 4. (2x + 4)x = 390

step 5. 2x^2 +4x = 390

step 6. 2x^2 + 4x - 390 = 0

step 7. -4 +- sqr(4^2 -4(2)(-390))/2(2) quadratic formula

step 8. (-4 +- sqr(3136))/4

step 9. (-4 +- 56)/4

step 10. x = 13yd, l = 2x + 4 = 2(13) + 4 = 30yd.

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

step-by-step explanation: