The quality-control department of Starr Communications, the manufacturer of video-game cartridges, has determined from records that 1.6% of the cartridges sold have video defects, 0.7% have audio defects, and 0.4% have both audio and video defects. (a) What is the probability that a cartridge purchased by a customer will have a video or audio defect?

The probability that a cartridge purchased by a customer will have a video or audio defect is 1.9%

Step-by-step explanation:

The given parameters in the question are;

The percentage of cartridges that have video defects, P(X) = 1.6%

The percentage of cartridges that have audio defects, P(Y) = 0.7%

The percentage of cartridges that have both audio and video defects, P(X and Y) = 0.4%

The probability is with regards to inclusive evets

The probability of inclusive events 'X' and 'Y' which are events that can happen at the same time are given as follows;

P(X or Y) = P(X) + P(Y) - P(X and Y)

Therefore, we have;

P(X or Y) = P(Video or Audio) = 0.016 + 0.007 - 0.004 = 0.019

∴ P(Video or Audio) = 1.9%

The probability that a cartridge purchased by a customer will have a video or audio defect = 1.9%

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

i believe that the answer is

b. y-1=-2(x-4)

hope this !