The perimeter of a rectangle equals the sum of twice its length and twice its width. A rectangle has a length of 4n + 3 units and a width of 3n units. Write an expression for the perimeter of this rectangle in simplest form.

Perimeter of the rectangle = 14n + 6 units

Step-by-step explanation:

Perimeter of a rectangle = (2 * length) + (2 * width)

Perimeter of a rectangle = 2(length + width)

Length of the rectangle = 4n + 3 units

Width of the rectangle = 3n units

Perimeter of the rectangle = 2(length + width)

= 2{(4n + 3) + 3n}

= 2(4n + 3 + 3n)

= 2(7n + 3)

= 14n + 6

Perimeter of the rectangle = 14n + 6 units

sin3a=12/15

step-by-step explanation:

since one side was multiplied by 3 the other side must also be multiplied by 3.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3