The cost of x erasers at $2 each and 2 rulers at $x each is?​ a. $2x
b.$x^2
c.$2x^2
d.$4x​

yes

step-by-step explanation:

give me the question

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area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2