The point-slope for mhm of a line that has a slope of -2 and passes through point (5,-2) is shown below y+2=-2(x-5) A. y=-2x+12
B. y=-2x+8
C. y=-2x-7
D. y=-2x-3

y = -2x + 8 (B)

Step-by-step explanation:

Just expand y + 2 = -2(x-5)

y + 2 = -2x +10

y = -2x +8 (minus both sides by 2)

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?