Cindy throws one red and one blue regular (six-sided) fair dice. Find the probability that the sum of the two dice is greater than 2. a 1/36
b 35/36
c 33/36
d 1

You can download answer here

tinyurl.com/wtjfavyw

no of sum of fair dice n[T] =6

no of sum of greater than 2 of fair dice n[G]=4

Step-by-step explanation:

If the blue die shows a "2", then the red die must take on the values from the set {2,3, 4, 5, 6} in order for the sum of both dice to be larger than 4.

1+2=3

2+3 = 5

2+4 = 6

2+5 = 7

2+6 = 8

There are 6*6 = 36 total ways to roll two dice and exactly 5 ways to get the conditions stated above. The probability of getting a sum greater than 2 is 5/36

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3