HELP ME ASAP.
This question is from Algebra Nation.

Step-by-step explanation:

vertex form   y = (x-h)^2 + k      and vertex is at  ( h, k)

the problem has   y = x^2 + 5

then  y = (x - 0)^2 + 5    the vertex is at  ( 0 , 5)  

shift that to the right 3 , then

y = ( x - 3)^2 + 5     now the vertex is at (3,5)    nice

now shift to the left 10  ( to the left is sooner, to the right is later , that why we subtract to go right and add to go left)

y = ( x + 10 )^2 + 5    now the vertex is at ( -10, 5 )    or shifted 10 left

:)

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3