1 5 ,centeredattheorigin. y x -10 10 -10 10 0 S T U S(5, -10) → S′( , ) T(10, -10) → T′( , ) U(5, 10) → U′( , )

The answer is below

Step-by-step explanation:

Write the coordinates of the vertices after a dilation with a scale factor of 1/5 , centered at the origin.

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, dilation and translation.

Dilation is the reduction or enlargement in the size of an object by a scale factor (k). If k > 1, it is an enlargement and if k < 1, it is a reduction. If a point A(x, y) is dilated by a factor k, the new point is A'(kx, ky).

Therefore, if the vertices are dilated with a scale factor of 1/5 , centered at the origin. The new point is:

S(5, -10) → S′(1 , -2) T(10, -10) → T′(2 , -2) U(5, 10) → U′(1 , 2)

j

j

Step-by-step explanation:

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.