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Mathematics, 23.03.2021 17:00 annethelusma25

Hey can you state what's wrong in the given solution. =》

we know, zero is always equal to zero

=》
because, 16 - 16 = 0
and 20 - 20 = 0

=》

taking 4 as common from 16 - 16 and 5 as common from 20 - 20
now dividing both sides by
(4 - 4)

=》
=》
because, (4 - 4) in denominators of both sides cancels out (4 - 4) in numerator of both sides.

=》
we know, 4 = 2 + 2 , so plugging (2 + 2) in place of 4


0 = 0
16 - 16 = 20  - 20
4(4 - 4) = 5(4 - 4)
\frac{4(4 - 4)}{(4 - 4)}  =  \frac{5(4 - 4)}{(4 - 4)}
4 = 5
2 + 2 = 5

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Answers: 1

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Hey can you state what's wrong in the given solution. =》


we know, zero is always e...
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