Chloe has $2 worth of dimes and quarters. She has 13 more dimes than quarters. By following the steps below, determine the number of dimes, x, x, and the number of quarters, y, y, that Chloe has. Determine THREE WAYS to have 13 more dimes than quarters:

(delta math)

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number of dimes = 15

number of quarters = 2

Step-by-step explanation:

total money = $2 = 200 cents

types of coins are dimes and quarters

number of dimes are 13 more than quarters

let number of dimes be x and quarters be y

so our equation =

10x + 25y = 200

x = (y+13)

10(y+13) +25y= 200

10y + 130 +25y = 200

35y + 130 = 200

y = 70/35 = 2

cross checking :

x = y+13 = 15

amount = 10x15 + 25x2 = 150 + 50 = 200 cents = $2.

determine 3 ways to have 13 more dimes than quarters:

we can use linear equations and tables to solve.

total amount to be paid = $19.5

step-by-step explanation:

given ,

original price = $25.99

discount = 25%

discount amount = 25% of original price

discount amount = 25/100   * 25.99

discount amount = $6.49

hence , the total amount to be paid = original price - discount amount

                                                            = $25.99 - $6.49

                                                            =$19.5

total amount to be paid = $19.5

7

step-by-step explanation: