Find the distance between points P(8, 2) and Q(3, 8) to the nearest tenth.

Step-by-step explanation:

The distance between two points is

d^2=(x2-x1)^2+(y2-y1)^2

d^2=(8-3)^2+(2-8)^2

d^2=5^2+(-6)^2

d^2=25+36

d^2=61

d=7.8 (rounded to nearest tenth)

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

b.-4 units

all you   do is count how many times you move