A private plane traveled from Seattle to a rugged​ wilderness, at an average speed of 132 mph. On the return​ trip, the average speed was 110 mph. If the total traveling time was 6 ​hours, how far is Seattle from the​ wilderness?

Brainliest PLEASE!

Step-by-step explanation:

a = seattle

b = wilderness

t = time traveling at 132 mph

(4-t) = time traveling at 110 mph

distance traveled at 132 mph = 132(t)

distance traveled at 110 mph = 110(4-t)

but the two distances are equal so:

132t = 110(4-t), solving for t

t = 1.82 hrs

d= 1.82 hrs * 132 m/hr = 240 miles

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

the infinity sign

step-by-step explanation: