Can someone please answer these for me I’m very confused. I need the answers by 20 minutes

12) y = 2x + 8

13) ( -4, 3)

14) y + 3 = 1(x + 2) ; y = x - 1

Step-by-step explanation:

12) ( -2, 4) and (1, 10)

m=(y2-y1)/(x2-x1)

m= (10-4)/(1+2)

m=6/3

m = 2

y - y1 = m(x - x1)

y - 4 = 2(x + 2)

y - 4 = 2x + 4

y = 2x + 8

13)

y - y1 = m(x - x1)

y - 3 = 2(x +4)

( -4, 3)

14) ( -2, -3) and (4, 3)

m=(y2-y1)/(x2-x1)

m=(3+3)/(4+2)

m=6/6

m=1

y - y1 = m(x - x1)

y + 3 = 1(x + 2)

y + 3 = x + 2

y = x - 1

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

heyyy

step-by-step explanation: