Complete the square
to find the vertex
of this parabola.
x?+8y+2x - 23=0

The vertex of the parabola is;

([-1], [3])

Step-by-step explanation:

The given quadratic equation is presented as follows;

x² + 8·y + 2·x - 23 = 0

The equation of the parabola in vertex form is presented as follows;

y = a·(x - h)² + k

Where;

(h, k) = The vertex of the parabola

Therefore, we have;

x² + 8·y + 2·x - 23 = 0

8·y = -x² - 2·x + 23

y = 1/8·(-x² - 2·x + 23)

y = -1/8·(x² + 2·x - 23)

y = -1/8·(x² + 2·x + 1 - 23 - 1) = -1/8·(x² + 2·x + 1 - 24)

y =  -1/8·((x + 1)² - 24) =  -1/8·(x + 1)² + 3

Therefore, the equation of the parabola in vertex form is y =  -1/8·(x + 1)² + 3

Comparing with y = a·(x - h)² + k, we have;

a = -1/8, h = -1, and k = 3

Therefore, the vertex of the parabola, (h, k) = (-1, 3).

3: 2

step-by-step explanation:

shorter piece is 2: 3, so just reverse it, and you get 3: 2

the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0