In 2 mins., a conveyor belt moves 300 lbs. Of recycle aluminum from delivery truck to a storage area. A smaller belt moves the same quantity of cans the same distance in 18 mins. If both belts are used, find how long it takes to move the cans to the storage area

1.8 minutes or 108 seconds

Step-by-step explanation:

The question tells us that the larger belt moves 300 lbs in 2 mins. And this is equal to 150 lb per minute

The question also tells us that a smaller belt moves the same quantity of 300 lbs in 18 mins. And this is equal to an average of 16.667 lb per min.

Both belts will move at a rate of 166.667 lb per min.

So it will take them 300 / 166.667 = 1.8 min or 108 s.

Therefore, the answer is 1.8 min

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet