Richard states that the value of x for the equation 1/2(3x-16)=4/5(x-3) is equal to
-11.

Where did Richard make his first mistake?

1/2(3x-16)=4/5(x-3)

10(1/2(3x-16))=10(4/5(x-3))

5(3x-16)=8(x-3)

15x-80=8x-3

7x=-77

x=-11

answer: b.48 for

step-by-step explanation:

idk man good luck man

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92