In the straightedge and compass construction of the equilateral triangle below, which of the following reasons can you use to prove that
2 CAB = ZACB?
B
A. AB and AC are radii of the same circle, and AB and BC aradii
of the same circle, So AB = AC and AB = BC. AC and BC are
both congruent to AB, SO AC = BC. Thus, triangle ABC is an
equilateral triangle Faulat

use formula for the circle a=3.14

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0

answer: what is the question you're trying to ask?

step-by-step explanation: