2p2 - 11pq + 2407 O A. (2p-49)(p-49)
B. (2p-49)(p+ 49)
O C. (2p-49)(2p2 + 29)
O D. The polynomial is irreducible.

hiking down a winding trail.

step-by-step explanation:

so what is the problem what are they asking you to solve

step-by-step explanation:

so what is the problem what are they asking you to solve

aloha~! my name is zalgo and i am here to you out on this amazing day. to answer your question, yes, nonzero numbers can have a greatest common factor and that would be 1. still don't get it? let me considering every number is divisible by 1 and hence every number has 1 as a factor of theirs. so, if 2 nonzero numbers didn't share any gcf (greatest common factor), they would still have a factor in common and that would be 1.

i hope that this ! : p

"stay and stay proud! " - zalgo

(by the way, do you mind marking me as brainliest? i'd greatly appreciate it! mahalo! x3)