Use a linear approximation (or differentials) to estimate the given number. (Round your answer to two decimal places.) (1.999)3

Consider the function f(x) = x ³. Since 2³ = 8 is a perfect cube that is pretty close to x = 1.999, take the linear approximation to f(x) at x = 2. It is

f(x) ≈ L(x) = f (2) + f ' (2) (x - 2)

Compute the derivative:

f(x) = x ³   →   f ' (x) = 3x ²   →   f ' (2) = 12

Then

L(x) = 8 + 12 (x - 2) = 12x - 16

Now approximate 1.999³ :

f (1.999) ≈ L (1.999) = 12•1.999 - 16 = 7.988

(Compare this to the actual value, 7.98801.)

step-by-step explanation:

quartic functions has x = –1 and x = –2 as its only two real zeroes:

f(x) = a(x+2)(x+1)   a: real number

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