A watermelon is launched from a 25-foot tall platform at a carnival. The watermelon's height h (in feet) at time t seconds can be modeled by the equation h = -16t^2 + 56t + 25. Find the maximum height of the watermelon

The maximum height of the watermelon is 74 feet.

Step-by-step explanation:

The watermelon reaches its maximum height when its velocity is zero. Mathematically speaking, velocity is the first derivative of the function height, that is:

(1)

Where is the velocity, in feet per second.

If we know that and , then the time associated with maximum height is:

(2)

Now we evaluate the function height at time found in the previous step: ()

The maximum height of the watermelon is 74 feet.

b 1: 45 am

step-by-step explanation:

its that because if it was in the pm it would be 1345