since the equation for both triangles have A^2 + B^2 you can think of the two equations for C^2 and n^2 as a system of equations such as to what a equals in the first equation for A^2 + B^2 in the second question after you substitute to what equation do you get ​

Given:

a² + b² = c²

a² + b² = n²

To find:

Substituting both equation to get a new equation

Steps:

We know,

a² + b² = c²

a² + b² = n²

Now if we substitute a² + b² to equal to c², in equation a² + b² = n² we get,

a² + b² = n²

       c² = n²

         c = n

Therefore we get the new equation as c = n

Happy to help :)

If you need any help, pls feel free to ask

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

explanation:

step-by-step explanation: