In ΔFGH, the measure of ∠H=90°, the measure of ∠F=24°, and FG = 57 feet. Find the length of HF to the nearest tenth of a foot.

52.1

Step-by-step explanation:

\cos F = \frac{\text{adjacent}}{\text{hypotenuse}}=\frac{x}{57}

cosF=

hypotenuse

adjacent

​

=

57

x

​

\cos 24=\frac{x}{57}

cos24=

57

x

​

57\cos 24=x

57cos24=x

Cross multiply.

x=52.0721\approx \mathbf{52.1}\text{ feet}

x=52.0721≈52.1 feet

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1

11

step-by-step explanation:

32.50-7.50=25

225/25=11