The point P=\left(-\frac{\sqrt{33}}{7},\,\, y\right)P=(− 7 33 ​ ​ ,y) lies on the unit circle shown below. What is the value of yy in simplest form?

y = √-1040/7

Step-by-step explanation:

The equation of a unit circle is expressed as;

x²+y² = 1

Given the coordinate of P = (-33/7, y)

Substitute the coordinate into the give expression and find y;

(-33/7)²+y² = 1

Expand

y² = 1-(-33/7)²

According to difference of two square

y² = (1+(-33/7))1-(-33/7))

y² = (1-33/7)(1+33/7)

y² = -26/7(40/7)

y² = -1040/49

y= √-1040/49

y = √-1040/√49

y = √-1040/7

Hence the value of y is y = √-1040/7