Given a circle with a diameter whose endpoints are (-1, -1) and (5, 3), write the equation of the circle. Question 4 options:

(x−2)2+(y−1)2=13

(x−2)2+(y−1)2=169

(x−2)2+(y−1)2=26

(x+1)2+(y+1)2=52

(x+1)2+(y+1)2=26

yes

step-by-step explanation:

answer: c

(2, -4)

goes 7 to the

(9, 4)

easy

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0