Amotocross rider is in the air for 2.5 seconds. your camera can take a picture every 0.125 second. your friend's camera can take a picture every 0.15 second.

a. how much times faster is your camera than your friend's camera?

b. how many more pictures can you take while the rider is in the air?

a) Our camera is 1.2 times faster than friend's camera.

b) We can take 20 pictures while the rider is in the air.

Step-by-step explanation:

According to the given problem

a) 1 picture in our camera takes time =0.125 seconds

1 picture in friend's camera takes time =0.15 seconds

The rate of pictures taken by our camera=

The rate of pictures taken by friend's camera=

Now, scale factor by which our camera is faster then friend's camera=

Thus Our camera is 1.2 times faster than friend's camera.

b) Number of pictures we can take while the rider is in the air [∵Duration of motocross rider is in the air = 2.5 seconds.]

Thus we can take 20 pictures while the rider is in the air.

the expression (1.26)2t reveals the approximate rate of increases in the number of plants semiannually.

hope this : )

300pi

step-by-step explanation: