If angle A is congruent to itself by the Reflexive Property, which transformation could be used to prove ΔABC ~ ΔADE by AA similarity postulate? triangles ABC and ADE, in which point D is between points A and B and point E is between points A and C

Translate triangle ADE so that point D lies on point B to confirm ∠D ≅ ∠B.
Translate triangle ADE so that point B lies on point E to confirm ∠B ≅ ∠E.
Dilate ΔABC from point A by the ratio segment AD over segment AB to confirm segment AD ~ segment AB.
Dilate ΔABC from point A by the ratio segment AE over segment AC to confirm segment AE ~ segment AC.

answer: was that a question or answer?

step-by-step explanation:

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.