The axis of symmetry for the graph of the function f(x) = 3x^2 + bx + 4 is x = 3/2 . What is the value of b?

b = -9

Step-by-step explanation:

Axis of symmetry of a parabola = -b / 2a.

Where y = ax² + bx + c.

Given f(x) = 3x^2 + bx + 4,

a = 3, and c = 4.

If the axis of symmetry is 3/2, than b can be found by substitution and algebra.

[ x = -b / 2a ] → [ 3 / 2 = -b / 2a ] →

[ 3 / 2 = -b / 2 (3) ] → [ 3 / 2 = -b / 6 ] →

[ 3 / 2 × 6 = -b / 6 × 6 ] → [ 18 / 2 = -b ] →

[ 9 = -b ] → [ -b = 9 ] → [ (-)(-b) = (-)(9) ] →

b = -9

the answer is 13 cm

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .