A population of bacteria grows according to the function p(t) = po · 1.42, where t is measured in hours. If the initial population size was 1,000 cells, approximately hoy long will the it take the population to exceed 10,000
cells? Round your answer to the nearest tenth.

The time duration for the population to exceed 10,000 is approximately 6.6 hours

Step-by-step explanation:

The given equation for the population of a bacteria is presented as follows;

Where;

t = The time duration in hours

The initial population of the cells = 1,000

Therefore, at t = 0, P(0) = 1,000 = P₀ × 1.42^0

∴  P(0) = 1,000 = P₀ × 1 = P₀

P₀ = 1,000

When the population is 10,000, we have;

P(t) = 10,000 = 1,000 × 1.42^t

∴ 1.42^t = 10,000/1,000 = 10

㏒(1.42^t) = ㏒(10) = 1

∴ t × ㏒(1.42) = 1

t = 1/㏒(1.42) = 6.56649071898

∴ The time duration for the population to exceed 10,000, t ≈ 6.6 hours.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐