A bag contains 2 red pens, 4 blue pens, 3 black pens, and 1 green pen. Once a pen is selected, it is replaced, and then another pen is selected. Determine P(blue and blue)

Given:

A bag contains 2 red pens, 4 blue pens, 3 black pens, and 1 green pen.

Once a pen is selected, it is replaced, and then another pen is selected.

To find:

The probability of getting blue pens in both draws, i.e., P(blue and blue).

Solution:

We have,

Number of red pens = 2

Number of blue pens = 4

Number of black pens = 3

Number of green pen = 1

Total number of pens =

                                    =

The probability of getting a blue pen is:

Once a pen is selected, it is replaced, and then another pen is selected. So, after replacement the probability of getting a blue is remains the same.

Therefore, the value of is 0.16.

d is the only accurate one

step-by-step explanation:

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629