What is the slope of the line that passes through the points (7.-12) and (-9,36)?​

Step-by-step explanation:

m = slope where

m = rise / run

rise = y2 - y1  

run = x2 - x1

where  

the given point P1 = (7, -12)

and is in the form of (x1,y1)  

and

the given point P2 = (-9,36)  

is  in   the   form  of   (x2,y2)

then

m =  ( y2 - y1 ) / ( x2 - x1 )

m = ( 36 - (-12) ) / ( -9 -7 )

m = ( 36 + 12 ) /  ( - 16 )

m =  48 /  - 16

m = - 3

the slope is negative 3

slope = - 3

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180