Solve the equation. (Find all solutions of the equation in the interval [0, 2pi). Enter your answers as a comma-separated list.) (3 sin(2x) + 3 cos(2x))^2=9

I got

5.53+2pi times n

WORK:

Solve for x

While -1 is a solution, it isn't within the interval of 0,2pi.

However, we can use the reference angle identity

So some more possible points are

Since it on a interval, it must be less than 2 pi or 6.28.

Let find some more points

So 5.28 is a point,

That is too big since -6.28 is smaller than 7.03

We can use the identity

1 is smaller than 2pi so it is true.

Negative 3/4 is smaller than zero so it not a solution.

Make sure to include

so

We can also -3/4 plus 2 pi.

Which is about 6

5.53.

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry