Veronikas five test scores are 59 80 95 and 93 if the outlier of 59 is removed what is the mean absolute deviation of the remaining four test scores?

Complete Question

Veronikas four test scores are 59, 80, 95, 88 and 93 if the outlier of 59 is removed what is the mean absolute deviation of the remaining four test scores?

5

Step-by-step explanation:

We have the four test scores

80, 95, 88 and 93

Step 1

We find the mean of the 4 test scores

= 80 + 95 + 88 + 93/4

= 356 / 4

89

Step 2

The formula for Mean Absolute Deviation =

Summation( x - Mean)/n

Hence,

|(80 - 89 )+( 95 - 89) + (88 - 89) + (93 - 89)|/5

= 9 + 6 +1 + 4/4

= 20/4

= 5

x equals 1

step-by-step explanation:

f(4)=f(×)

x=1