Find the AROC for 6x-9 for the interval x=0 to x=2

AROC =6

Step-by-step explanation:

Let f(x)=6x-9

When x=2

f(2) =6(2)-9 = 3

When x=0

f(0)=6(0)-9 =-9

So, average rate of change AROC= =6

So, AROC=6

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

17.08

correct me if i am wrong.