If an object is projected upward with an initial velocity of 125 ft per sec, its height h after t seconds is h= - 16t+ 125t. Find the height of the object after 2 seconds.​

h(t) = -16t^2+125t

We need to find h(t) when t = 4 s:

h(4) = -16*4^2+125*4

h(4) = 244 ft

The height of the object after 4 seconds is 244 feet.

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.