Name Properties of Parallelograms
Remember
1. A parallelogram is a quadrilateral (four-sided polygon) with these properties:
its opposite sides are parallel
Its opposite soos are congruent
its opposito angles are congruent
. its diagonals bisect each other
2. A rhombus is a parallelogram with four congruent sides its diagonala
are perpendicular to each other and bisect opposite angles.
A rectangle is a paralelogram with four right angles.
Its diagonals are congruent.
4 Asquare is a parallelogram with four congruent sides and
lour right angles. A square is both a thombus and a rectangle
Use the properties to solve for the missing measures Shade your answers below to
reveal the answer to the riddle: What keeps a square from moving?
1. Given: VWXY is a paralelogram. Vw-14 WX-0 V.5.5
MVYX 52 m2 40 m3 20
a XY
& m: VWX
b. VX
d. m. YVW- 1. mi
2. Given: PQRS is a rhombur. PQ-4 mAPOR60
OR
ST
23
a PT
t. m2 SPQ
3. Given: JKLM is a rectangle. JK - 10 N212 mt 53
m. NL
6. MR
MJN
# MN
4. Given: ABCD is a square AB
BC
1. MLADC
AC.
1. MODC
To
24

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0

a king of hearts and a 2 of spades

what is the approximate solution for the system of equations x+5y=10 and 3x+y=1

step-by-step explanation:

tell me the answer first then i will answer it